Finding The 7th Term In A Geometric Sequence A Step-by-Step Guide

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Finding a specific term in a sequence is a fundamental concept in mathematics, particularly in the study of sequences and series. In this comprehensive guide, we will delve into the process of identifying the 7th term in the sequence 13,1,3,9,…{\frac{1}{3}, 1, 3, 9, \ldots}. We will explore the underlying principles, provide a step-by-step solution, and discuss the significance of formulas in solving such problems. Whether you're a student learning about sequences or someone looking to refresh your math skills, this article will provide you with a clear and concise understanding of how to tackle these types of problems.

Understanding Sequences and Common Ratios

Sequences are ordered lists of numbers, often following a specific pattern or rule. Each number in a sequence is called a term. Identifying the pattern is crucial for finding any term in the sequence. In the given sequence, 13,1,3,9,…{\frac{1}{3}, 1, 3, 9, \ldots}, we observe that each term is obtained by multiplying the previous term by a constant value. This constant value is known as the common ratio. To find the common ratio, we can divide any term by its preceding term. For instance, dividing 1 by 13{\frac{1}{3}} gives us 3, and dividing 3 by 1 also gives us 3. Thus, the common ratio in this sequence is 3. Understanding the concept of common ratio is essential for identifying the type of sequence and applying the appropriate formula to find a specific term.

Identifying Geometric Sequences

In the realm of mathematical sequences, geometric sequences hold a prominent position due to their consistent multiplicative pattern. A geometric sequence is characterized by a constant ratio between successive terms, which we've already identified as the common ratio. This constant ratio is the defining feature that distinguishes geometric sequences from other types of sequences, such as arithmetic sequences (where terms increase by a constant difference) or more complex sequences with varying patterns. Recognizing a sequence as geometric allows us to leverage specific formulas and techniques designed for these types of sequences, making it significantly easier to calculate terms that are further along in the sequence. The ability to quickly identify a geometric sequence is a valuable skill in mathematics, enabling efficient problem-solving and a deeper understanding of sequence behavior. In our given sequence, 13,1,3,9,…{\frac{1}{3}, 1, 3, 9, \ldots}, the consistent multiplication by 3 confirms that it is indeed a geometric sequence.

The Importance of the Common Ratio

The common ratio serves as the cornerstone for understanding and working with geometric sequences. It dictates the rate at which the sequence grows or diminishes, and it's the key to unlocking the sequence's overall pattern. Without identifying the common ratio, it would be nearly impossible to predict future terms or derive a general formula for the sequence. In practical terms, the common ratio allows us to extrapolate the sequence indefinitely, calculating terms far beyond those initially provided. For instance, knowing that the common ratio is 3 in our sequence, we can confidently state that each term is three times larger than the one before it. This predictability is incredibly useful in various mathematical applications, from financial calculations involving compound interest to scientific models involving exponential growth or decay. The common ratio, therefore, is not just a number; it's a powerful tool that provides insight into the fundamental behavior of a geometric sequence.

The Formula for the nth Term of a Geometric Sequence

To efficiently find any term in a geometric sequence, we use a specific formula. This formula is derived from the fundamental principle of geometric sequences, where each term is the product of the previous term and the common ratio. The formula for the nth{n^{th}} term (an{a_n}) of a geometric sequence is given by:

an=a1imesr(n−1){ a_n = a_1 imes r^{(n-1)} }

Where:

  • an{a_n} is the nth{n^{th}} term we want to find.
  • a1{a_1} is the first term of the sequence.
  • r{r} is the common ratio.
  • n{n} is the term number we are looking for.

This formula encapsulates the essence of geometric progression, allowing us to calculate any term directly without having to compute all the preceding terms. It's a powerful tool that simplifies the process of working with geometric sequences, especially when dealing with terms that are far down the sequence. Understanding and applying this formula is crucial for solving a wide range of problems related to geometric sequences and series.

Breaking Down the Formula

To truly appreciate the power and utility of the formula an=a1imesr(n−1){a_n = a_1 imes r^{(n-1)}}, it's essential to break down each component and understand its role in determining the nth{n^{th}} term of a geometric sequence. The first term, a1{a_1}, serves as the starting point of the sequence. It's the initial value from which all subsequent terms are derived through multiplication by the common ratio. The common ratio, r{r}, as we've discussed, is the constant factor that dictates the multiplicative growth or decay of the sequence. It's the heart of the geometric progression, determining how rapidly the terms increase or decrease. The term number, n{n}, is the position of the term we're interested in finding. It could be the 5th term, the 10th term, or any other term in the sequence. The exponent (n-1) in the formula is a crucial element that reflects the number of times the common ratio is applied to the first term to reach the nth{n^{th}} term. By understanding how these components interact within the formula, we can effectively calculate any term in a geometric sequence with precision and confidence.

Advantages of Using the Formula

Utilizing the formula an=a1imesr(n−1){a_n = a_1 imes r^{(n-1)}} offers several key advantages when working with geometric sequences, making it an indispensable tool for mathematicians, students, and anyone dealing with these types of sequences. Firstly, it provides a direct method for finding any term in the sequence without the need to calculate all the preceding terms. This is particularly valuable when dealing with terms that are far down the sequence, as it saves significant time and effort. Secondly, the formula encapsulates the underlying pattern of geometric sequences in a concise mathematical expression. This not only simplifies calculations but also enhances our understanding of how these sequences behave. Thirdly, the formula is universally applicable to any geometric sequence, regardless of the specific values of the first term and common ratio. This versatility makes it a powerful tool for solving a wide range of problems. Finally, the formula allows for efficient analysis and prediction of sequence behavior, which is essential in various applications, such as financial modeling, population growth studies, and physics. In essence, the formula is a cornerstone for understanding and manipulating geometric sequences, providing both practical computational benefits and deeper conceptual insights.

Applying the Formula to Find the 7th Term

Now that we have the formula and a clear understanding of its components, let's apply it to find the 7th term of the sequence 13,1,3,9,…{\frac{1}{3}, 1, 3, 9, \ldots}. First, we identify the values we need:

  • The first term, a1=13{a_1 = \frac{1}{3}}.
  • The common ratio, r=3{r = 3} (as calculated earlier).
  • The term number we want to find, n=7{n = 7}.

Substituting these values into the formula, we get:

a7=13imes3(7−1){ a_7 = \frac{1}{3} imes 3^{(7-1)} }

a7=13imes36{ a_7 = \frac{1}{3} imes 3^6 }

Now, we calculate 36{3^6}, which is 729. So, the equation becomes:

a7=13imes729{ a_7 = \frac{1}{3} imes 729 }

Finally, we multiply 13{\frac{1}{3}} by 729, which gives us 243. Therefore, the 7th term of the sequence is 243. This step-by-step application demonstrates how the formula can be used to efficiently find any term in a geometric sequence, making it a powerful tool for solving mathematical problems.

Step-by-Step Calculation

To further illustrate the application of the formula and ensure clarity, let's walk through the step-by-step calculation of the 7th term in our sequence. This detailed breakdown will help solidify your understanding of the process and highlight the importance of each step.

  1. Identify the values: As we mentioned earlier, we first identify the values needed for the formula. The first term a1{a_1} is 13{\frac{1}{3}}, the common ratio r{r} is 3, and the term number n{n} is 7.
  2. Substitute the values: Next, we substitute these values into the formula an=a1imesr(n−1){a_n = a_1 imes r^{(n-1)}}, which gives us a7=13imes3(7−1){a_7 = \frac{1}{3} imes 3^{(7-1)}}.
  3. Simplify the exponent: We simplify the exponent by calculating 7−1{7-1}, which equals 6. Our equation now looks like this: a7=13imes36{a_7 = \frac{1}{3} imes 3^6}.
  4. Calculate the power: We calculate 36{3^6}, which means 3 multiplied by itself six times. This equals 729. So, the equation becomes a7=13imes729{a_7 = \frac{1}{3} imes 729}.
  5. Perform the multiplication: Finally, we perform the multiplication. Multiplying 13{\frac{1}{3}} by 729 gives us 243. Thus, a7=243{a_7 = 243}.

By following these steps, we have clearly demonstrated how to use the formula to find the 7th term of the geometric sequence. This methodical approach ensures accuracy and a deeper comprehension of the underlying mathematical principles.

Verification and Alternative Methods

To ensure the accuracy of our result and gain a more holistic understanding of the problem, it's beneficial to explore verification methods and alternative approaches. One way to verify our answer is to manually calculate the terms of the sequence up to the 7th term. Starting with 13{\frac{1}{3}}, we multiply by 3 successively:

  • 1st term: 13{\frac{1}{3}}
  • 2nd term: 13imes3=1{\frac{1}{3} imes 3 = 1}
  • 3rd term: 1imes3=3{1 imes 3 = 3}
  • 4th term: 3imes3=9{3 imes 3 = 9}
  • 5th term: 9imes3=27{9 imes 3 = 27}
  • 6th term: 27imes3=81{27 imes 3 = 81}
  • 7th term: 81imes3=243{81 imes 3 = 243}

This manual calculation confirms that our result of 243 for the 7th term is indeed correct. Another alternative method involves using the recursive definition of a geometric sequence, where each term is defined in relation to the previous term. However, for finding a specific term far down the sequence, the formula an=a1imesr(n−1){a_n = a_1 imes r^{(n-1)}} remains the most efficient and direct approach. By verifying our answer and considering alternative methods, we reinforce our understanding and build confidence in our problem-solving skills. This practice is invaluable in mathematics and beyond, promoting both accuracy and a deeper conceptual grasp.

Conclusion

In conclusion, finding the 7th term in the sequence 13,1,3,9,…{\frac{1}{3}, 1, 3, 9, \ldots} highlights the importance of understanding geometric sequences and the application of the formula an=a1imesr(n−1){a_n = a_1 imes r^{(n-1)}}. By identifying the common ratio, recognizing the sequence as geometric, and correctly substituting the values into the formula, we were able to efficiently determine that the 7th term is 243. This process not only provides a solution to the specific problem but also reinforces the fundamental principles of sequences and series. Mastering these concepts is crucial for further studies in mathematics and various real-world applications where patterns and progressions play a significant role. Whether you're calculating compound interest, predicting population growth, or analyzing scientific data, the ability to work with sequences and series is an invaluable skill. We encourage you to practice with different sequences and problems to solidify your understanding and build your mathematical confidence.