Calculate Probability Aron Flips A Penny 9 Times For Exactly 3 Heads

by Scholario Team 69 views

This article explores the problem of calculating the probability of getting exactly 3 heads when flipping a penny 9 times. This is a classic probability problem that can be solved using the binomial probability formula. We will break down the formula, apply it to the specific scenario, and discuss the reasoning behind each step. Whether you're a student learning probability or just curious about how these calculations work, this guide will provide a clear and comprehensive explanation.

Understanding the Binomial Probability Formula

In the realm of probability, the binomial probability formula stands as a powerful tool for calculating the likelihood of a specific number of successes in a series of independent trials, each with the same probability of success. This formula is particularly useful in scenarios where there are only two possible outcomes for each trial, often referred to as success and failure. Flipping a coin, where the outcome is either heads or tails, perfectly exemplifies this type of scenario. The binomial probability formula is expressed as:

P(k successes)=nCkpk(1−p)n−kP(k \text{ successes}) = {}_n C_k p^k(1-p)^{n-k}

Where:

  • P(k successes) represents the probability of obtaining exactly k successes.

  • n denotes the total number of trials.

  • k signifies the number of successes we are interested in.

  • p represents the probability of success on a single trial.

  • {}_n C_k is the binomial coefficient, which calculates the number of ways to choose k successes from n trials. It is also known as the combination formula and is calculated as:

    nCk=n!(n−k)!k!{}_n C_k = \frac{n!}{(n-k)!k!}

    Where n! (n factorial) is the product of all positive integers up to n. For example, 5! = 5 × 4 × 3 × 2 × 1 = 120.

To fully grasp the formula, let's dissect each component. The term p^k represents the probability of getting k successes in a row, assuming each trial is independent. The term (1-p)^(n-k) represents the probability of getting (n-k) failures, again assuming independence. The binomial coefficient {}_n C_k accounts for the fact that there are multiple ways to arrange k successes within n trials. For instance, if we flip a coin 3 times and want 2 heads, the heads could occur on the first two flips, the first and last flips, or the last two flips. The binomial coefficient tells us how many such combinations exist.

The binomial probability formula is not just a mathematical equation; it's a framework for understanding and predicting probabilities in various real-world situations. Consider scenarios such as quality control in manufacturing, where we might want to calculate the probability of finding a certain number of defective items in a batch, or in medical research, where we might be interested in the probability of a treatment being effective for a certain number of patients. By understanding the interplay of trials, successes, and probabilities, the binomial formula empowers us to make informed decisions and predictions in a multitude of contexts. Its elegance lies in its ability to distill complex scenarios into a manageable equation, providing clarity and insight into the realm of chance.

Applying the Formula to the Penny Flipping Problem

In this specific scenario, Aron flips a penny 9 times, and we want to find the probability of getting exactly 3 heads. To apply the binomial probability formula effectively, we need to identify each component of the formula within the context of this problem. The first step is to determine the values of n, k, and p. Here, n represents the total number of trials, which corresponds to the number of times Aron flips the penny. Therefore, n = 9. Next, k represents the number of successes we are interested in, which in this case is the number of heads we want to obtain. So, k = 3. Finally, p represents the probability of success on a single trial. Since we are flipping a fair penny, the probability of getting a head on any given flip is 1/2, thus p = 1/2.

Now that we have identified the values of n, k, and p, we can substitute them into the binomial probability formula:

P(3 heads)=9C3(1/2)3(1−1/2)9−3P(3 \text{ heads}) = {}_9 C_3 (1/2)^3 (1-1/2)^{9-3}

This equation represents the probability of getting exactly 3 heads in 9 flips. The next step is to calculate each part of the equation separately before combining them. First, let's calculate the binomial coefficient, {}_9 C_3, which represents the number of ways to choose 3 heads from 9 flips. Using the formula for combinations, we have:

9C3=9!(9−3)!3!=9!6!3!{}_9 C_3 = \frac{9!}{(9-3)!3!} = \frac{9!}{6!3!}

Expanding the factorials, we get:

9C3=9×8×7×6×5×4×3×2×1(6×5×4×3×2×1)(3×2×1){}_9 C_3 = \frac{9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{(6 \times 5 \times 4 \times 3 \times 2 \times 1)(3 \times 2 \times 1)}

We can simplify this expression by canceling out the 6! terms:

9C3=9×8×73×2×1=5046=84{}_9 C_3 = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = \frac{504}{6} = 84

Thus, there are 84 different ways to get 3 heads in 9 coin flips. Next, we need to calculate (1/2)^3, which represents the probability of getting 3 heads in a row. This is simply:

(1/2)3=1/2×1/2×1/2=1/8(1/2)^3 = 1/2 \times 1/2 \times 1/2 = 1/8

Similarly, we need to calculate (1-1/2)^(9-3), which simplifies to (1/2)^6. This represents the probability of getting 6 tails in the remaining 6 flips:

(1/2)6=1/2×1/2×1/2×1/2×1/2×1/2=1/64(1/2)^6 = 1/2 \times 1/2 \times 1/2 \times 1/2 \times 1/2 \times 1/2 = 1/64

Now that we have all the components, we can plug them back into the binomial probability formula:

P(3 heads)=84×(1/8)×(1/64)P(3 \text{ heads}) = 84 \times (1/8) \times (1/64)

Calculating and Interpreting the Probability

Having dissected the binomial probability formula and computed its individual components for the penny flipping problem, we now arrive at the crucial stage of calculating the final probability and interpreting its meaning. We have established that there are 84 ways to obtain exactly 3 heads when flipping a penny 9 times. We've also calculated the probability of getting 3 heads in a row as 1/8 and the probability of getting 6 tails in the remaining 6 flips as 1/64. By multiplying these values together, we can determine the overall probability of the event.

Let's revisit the equation:

P(3 heads)=84×(1/8)×(1/64)P(3 \text{ heads}) = 84 \times (1/8) \times (1/64)

To compute the final probability, we multiply the numbers together:

P(3 heads)=84×(1/512)P(3 \text{ heads}) = 84 \times (1/512)

P(3 heads)=84/512P(3 \text{ heads}) = 84/512

To simplify the fraction, we can divide both the numerator and the denominator by their greatest common divisor, which is 4:

P(3 heads)=21/128P(3 \text{ heads}) = 21/128

Therefore, the probability of getting exactly 3 heads when flipping a penny 9 times is 21/128. This fraction represents the likelihood of the specific outcome we are interested in. But what does this number truly mean? To gain a more intuitive understanding, it's often helpful to convert the fraction into a decimal or a percentage.

Converting 21/128 to a decimal, we get approximately 0.164. Multiplying this by 100 gives us a percentage of 16.4%. So, there is approximately a 16.4% chance of getting exactly 3 heads when flipping a penny 9 times. This means that if we were to repeat this experiment many times, we would expect to get exactly 3 heads in about 16.4% of the trials.

This probability provides valuable insight into the distribution of outcomes when flipping a coin multiple times. While it may seem counterintuitive that the probability of getting exactly 3 heads is relatively low compared to other possible outcomes, it's important to remember that there are many different ways to arrange the heads and tails. The binomial coefficient accounts for these different arrangements, but the probabilities of the individual sequences (e.g., HHTTTTTTT) are quite small. The overall probability is a balance between the number of possible arrangements and the probability of each specific arrangement.

Interpreting probabilities in this way allows us to make informed predictions and decisions based on chance. Whether it's assessing the likelihood of success in a business venture, evaluating the effectiveness of a medical treatment, or simply understanding the odds in a game of chance, the ability to calculate and interpret probabilities is a valuable skill in a wide range of contexts. The penny flipping problem, while simple in its setup, provides a powerful illustration of how probability theory can be applied to real-world situations.

Alternative Representations of the Solution

While the fraction 21/128 provides an exact representation of the probability of getting exactly 3 heads in 9 coin flips, it's beneficial to explore alternative representations to enhance understanding and facilitate comparisons. In this section, we will delve into expressing the solution as a decimal, a percentage, and discuss the implications of these different forms.

As we calculated earlier, converting the fraction 21/128 to a decimal yields approximately 0.164. This decimal representation offers a more immediate sense of the magnitude of the probability. It places the probability on a continuous scale from 0 to 1, where 0 represents impossibility and 1 represents certainty. A probability of 0.164 indicates that the event is not particularly likely, but it's far from impossible. This decimal form is useful for quick comparisons and for visualizing the probability on a number line.

To express the probability as a percentage, we multiply the decimal value by 100. Thus, 0.164 becomes 16.4%. Percentages are widely used in everyday communication and offer a relatable way to convey probabilities. Saying that there is a 16.4% chance of getting exactly 3 heads in 9 coin flips provides a clear sense of the likelihood of this outcome. Percentages are particularly helpful when comparing probabilities across different scenarios, as they provide a standardized scale out of 100.

Furthermore, understanding the probability in terms of odds can offer another perspective. Odds express the ratio of the probability of an event occurring to the probability of it not occurring. In this case, the probability of getting exactly 3 heads is 21/128, and the probability of not getting exactly 3 heads is 1 - 21/128 = 107/128. The odds in favor of getting exactly 3 heads are therefore 21:107, meaning that for every 21 times we expect to get exactly 3 heads, we expect to get a different number of heads 107 times. This representation is commonly used in gambling and other contexts where the relative likelihood of success and failure is of interest.

Each of these representations—fraction, decimal, percentage, and odds—offers a unique way to interpret the probability of getting exactly 3 heads in 9 coin flips. The fraction provides the exact value, the decimal places it on a continuous scale, the percentage offers a relatable measure out of 100, and the odds compare the likelihood of success to failure. By understanding these different forms, we can communicate probabilities more effectively and gain a deeper appreciation for the nuances of chance.

Conclusion

In conclusion, the problem of determining the probability of getting exactly 3 heads when flipping a penny 9 times provides a practical application of the binomial probability formula. By carefully identifying the parameters n, k, and p, we can apply the formula to calculate the probability, which we found to be 21/128, or approximately 16.4%. This result highlights the power of probability theory in predicting the likelihood of specific outcomes in repeated trials. Understanding the binomial probability formula and its application not only enhances our mathematical skills but also provides a framework for analyzing various real-world scenarios involving chance and uncertainty. The ability to calculate and interpret probabilities is a valuable asset in decision-making and problem-solving across diverse fields.